Grade 11 Physical Sciences · Mechanics · Paper 1 (Physics)

Newton's Law of Universal Gravitation Grade 11

Real Newton's Law of Universal Gravitation past paper questions from 2018 to 2021 and practice questions, with each memo split into the ticks examiners give. Try one, mark yourself, and see exactly which skill cost you marks.

questions · 22 past paper, 47 practice: 69 questions · 22 past paper, 47 practice
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videos: 3 videos

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Question 1.2 · November 2019 · Paper 1 · National (DBE) · 2 marks

Various options are provided as possible answers to the following questions. Choose the answer and write only the letter (A–D) next to the question numbers (1.1 to 1.10).

1.2 Which ONE of the following statements regarding inertia of an object is CORRECT?

The inertia of an object ...(2)

A is greater if its mass is smaller.
B increases as the applied force on the object increases.
C is the resistance to any change in its state of motion.
D increases as the frictional force on the object increases.

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Newton's Law of Universal Gravitation skills

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More Newton's Law of Universal Gravitation Grade 11 questions and answers

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4. Question 4.1 · November 2018 · Paper 1 · National (DBE) · 2 marks
Learners investigate the relationship between the mass of an object and the acceleration it experiences when a constant net force is applied on the object. They use their results to draw the graph below.
4.1 State *Newton's Second Law of Motion* in words.(2)
Show the memo (2 ticks)Memo
1. ✓
  Directly proportional to the net forceWhen a resultant/net force acts on an object, the object will accelerate in the direction of the force. The acceleration is directly proportional to the net force
  1 mark · State Newton's laws and force terms
2. ✓
  Inversely proportional to the massand inversely proportional to the mass of the object.
  1 mark · State Newton's laws and force terms
5. Question 1.6 · November 2021 · Paper 1 · Provincial · 2 marks
Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Choose the answer and write only the letter (A–D).
1.6 A $10$ kg object is located at $1, 9 \times 1 0^{6}$ m from the centre of a larger object whose mass is $8, 4 \times 1 0^{24}$ kg.

What is the size of the force acting on the smaller object?(2)
1. A $1552, 02$ N
2. B $29, 48 \times 1 0^{8}$ N
3. C $1552, 02$ kg
4. D $29, 48 \times 1 0^{8}$ kg
Show the memo (2 ticks)Memo
1. ✓
  Correct option $F = \frac{G m _{1} m _{2}}{r ^{2}} = \frac{( 6 , 67 \times 1 0 ^{- 11} ) ( 10 ) ( 8 , 4 \times 1 0 ^{24} )}{( 1 , 9 \times 1 0 ^{6} ) ^{2}} = 1552, 02$ N
  Force is measured in newtons, so C and D are ruled out by their unit.
  
  Answer: A
  2 marks · Apply Newton's law of gravitation
6. Question 2.3 · November 2021 · Paper 1 · Provincial · 3 marks
A bald eagle with a mass of $5$ kg is perched on a light, inextensible rope between two poles as shown in the diagram. The eagle is stationary on the rope.
2.3 Calculate the weight of the eagle.(3)
Show the memo (3 ticks)Memo
1. ✓
  Formula $F_{g} = m g$
  1 mark · Calculate weight
2. ✓
  Substitution $F_{g} = (5) (9, 8)$
  1 mark · Calculate weight
3. ✓
  Answer with unit $F_{g} = 49$ N (downwards)
  1 mark · Calculate weight
7. Practice · Siyavula Grade 11 Physical Sciences · Ex 2.7 · 3 marks
When the planet Jupiter is closest to Earth it is $6, 28 \times 1 0^{8}$ km away. If Jupiter has a mass of $1, 9 \times 1 0^{27}$ kg, what is the magnitude of the gravitational force between Jupiter and the Earth?(3)
Show the memo (3 ticks)Memo
1. ✓
  Formula $F = \frac{G m _{1} m _{2}}{r ^{2}}$
  1 mark · Apply Newton's law of gravitation
2. ✓
  Substitution $F = \frac{( 6 , 67 \times 1 0 ^{- 11} ) ( 5 , 98 \times 1 0 ^{24} ) ( 1 , 9 \times 1 0 ^{27} )}{( 6 , 28 \times 1 0 ^{11} ) ^{2}}$
  1 mark · Apply Newton's law of gravitation
3. ✓
  Answer $F = 1, 92 \times 1 0^{18} N$
  1 mark · Apply Newton's law of gravitation
Question adapted from Siyavula Education (CC BY 3.0) · Solution by NavyBlue
8. Practice · Siyavula Grade 11 Physical Sciences · Ex 2.7 · 3 marks
When the planet Jupiter is furthest from the Earth it is $9, 28 \times 1 0^{8}$ km away. If Jupiter has a mass of $1, 9 \times 1 0^{27}$ kg, what is the magnitude of the gravitational force between Jupiter and the Earth?(3)
Show the memo (3 ticks)Memo
1. ✓
  Formula $F = \frac{G m _{1} m _{2}}{r ^{2}}$
  1 mark · Apply Newton's law of gravitation
2. ✓
  Substitution $F = \frac{( 6 , 67 \times 1 0 ^{- 11} ) ( 5 , 98 \times 1 0 ^{24} ) ( 1 , 9 \times 1 0 ^{27} )}{( 9 , 28 \times 1 0 ^{11} ) ^{2}}$
  1 mark · Apply Newton's law of gravitation
3. ✓
  Answer $F = 8, 80 \times 1 0^{17} N$
  1 mark · Apply Newton's law of gravitation
Question adapted from Siyavula Education (CC BY 3.0) · Solution by NavyBlue
9. Practice · Siyavula Grade 11 Physical Sciences · Ex 2.7 · 5 marks
What distance must a satellite with a mass of $80$ kg be away from the Earth to feel a force of $1000$ N? How far from Jupiter to feel the same force? (Mass of Jupiter $= 1, 9 \times 1 0^{27}$ kg)(5)
Show the memo (5 ticks)Memo
1. ✓
  Formula $F = \frac{G m _{1} m _{2}}{r ^{2}}$
  1 mark · Apply Newton's law of gravitation
2. ✓
  Substitution for the Earth $1000 = \frac{( 6 , 67 \times 1 0 ^{- 11} ) ( 5 , 98 \times 1 0 ^{24} ) ( 80 )}{r ^{2}}$
  1 mark · Apply Newton's law of gravitation
3. ✓
  Distance from the Earth $r = 5, 65 \times 1 0^{6} m$
  1 mark · Apply Newton's law of gravitation
4. ✓
  Substitution for Jupiter $1000 = \frac{( 6 , 67 \times 1 0 ^{- 11} ) ( 1 , 9 \times 1 0 ^{27} ) ( 80 )}{r ^{2}}$
  1 mark · Apply Newton's law of gravitation
5. ✓
  Distance from Jupiter $r = 1, 01 \times 1 0^{8} m$
  1 mark · Apply Newton's law of gravitation
Question adapted from Siyavula Education (CC BY 3.0) · Solution by NavyBlue
10. Practice · Siyavula Grade 11 Physical Sciences · Ex 2.7 · 5 marks
The radius of Jupiter is $71, 5 \times 1 0^{3}$ km and the radius of the moon is $1, 7 \times 1 0^{3}$ km, if the moon has a mass of $7, 35 \times 1 0^{22}$ kg work out the gravitational acceleration on Jupiter and on the moon. (Mass of Jupiter $= 1, 9 \times 1 0^{27}$ kg)(5)
Show the memo (5 ticks)Memo
1. ✓
  Formula $g = \frac{GM}{r ^{2}}$
  1 mark · Apply Newton's law of gravitation
2. ✓
  Substitution for Jupiter $g_{J} = \frac{( 6 , 67 \times 1 0 ^{- 11} ) ( 1 , 9 \times 1 0 ^{27} )}{( 71 , 5 \times 1 0 ^{6} ) ^{2}}$
  1 mark · Apply Newton's law of gravitation
3. ✓
  Answer for Jupiter $g_{J} = 24, 8 m \cdotp s^{- 2}$
  1 mark · Apply Newton's law of gravitation
4. ✓
  Substitution for the moon $g_{M} = \frac{( 6 , 67 \times 1 0 ^{- 11} ) ( 7 , 35 \times 1 0 ^{22} )}{( 1 , 7 \times 1 0 ^{6} ) ^{2}}$
  1 mark · Apply Newton's law of gravitation
5. ✓
  Answer for the moon $g_{M} = 1, 7 m \cdotp s^{- 2}$
  1 mark · Apply Newton's law of gravitation
Question adapted from Siyavula Education (CC BY 3.0) · Solution by NavyBlue

Newton's Law of Universal Gravitation Grade 11 videos

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