Grade 10 Maths · Algebra · Paper 1

Literal Equations Grade 10

Real Literal Equations past paper questions and answers from 2016 to 2023, with each memo split into the ticks examiners give. Try one, mark yourself, and see exactly which skill cost you marks.

past paper questions: 8 past paper questions
skill: 1 skill
videos: 1 videos

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Question 1.4 · March 2022 · Provincial · 2 marks

Four options are provided as possible answers to the following questions. Choose the correct option.

1.4 The formula for the volume of a cone is

V = \frac{1}{3} π r^{2} h

. The radius,

r

, of the cone may be expressed as:(2)

A $\frac{3 V}{πh}$
B $\frac{V}{3 πh}$
C $3 \frac{V}{πh}$
D $\frac{1}{3} \frac{V}{πh}$

Work it out on paper first. Then mark yourself with the official memo, one tick at a time.

Literal Equations skills

Each skill is one thing a memo gives a tick for. Tap one for its own questions, notes and videos.

Change the subject of a formulaRearrange a formula to make a different letter the subject (for example from A = πr², make r the subject: r = √(A ÷ π)).46 past paper questions · 4 videos

More Literal Equations Grade 10 questions and answers

Try each one on paper before you open the memo.

4. Question 2.1.2 · March 2023 · Provincial · 3 marks
2.1 Solve for x:
2.1.2 $R = \frac{2 x}{3 S}$ (3)
Show the memo (3 ticks)Memo
1. ✓
  Multiplying by $3 S$ $3 RS = 2 x$
  1 mark · Change the subject of a formula
2. ✓
  Dividing by 2 $\frac{3 RS}{2} = x$
  1 mark · Change the subject of a formula
3. ✓
  Answer $x = (\frac{3 RS}{2})^{2} = \frac{9 R ^{2} S ^{2}}{4}$
  1 mark · Solve a surd equation
5. Question 2.1.3 · March 2021 · Provincial · 3 marks
2.1 Solve for x in each of the following equations:
2.1.3 $g = \frac{1 + 2 x}{x}$ (3)
Show the memo (3 ticks)Memo
1. ✓
  $gx$ on the left-hand side $gx = 1 + 2 x$
  1 mark · Change the subject of a formula
2. ✓
  Factorisation $gx - 2 x = 1$
  $x (g - 2) = 1$
  1 mark · Change the subject of a formula
3. ✓
  Solve for x $x = \frac{1}{g - 2}$
  1 mark · Change the subject of a formula
6. Question 2.1.4 · March 2020 · Provincial · 3 marks
2.1 Solve for x:
2.1.4 $x = y + x y$ (Make x the subject)(3)
Show the memo (3 ticks)Memo
1. ✓
  Isolate x terms $x - x y = y$
  1 mark · Change the subject of a formula
2. ✓
  Factorise x $x (1 - y) = y$
  1 mark · Change the subject of a formula
3. ✓
  Final expression $x = \frac{y}{1 - y}$
  1 mark · Change the subject of a formula
7. Question 3.1.2 · March 2018 · Provincial · 2 marks
3.1 Solve for $x$ :
3.1.2 $t = 2 π \frac{x}{g}$ (2)
Show the memo (2 ticks)Memo
1. ✓
  Isolate the root $\frac{t}{2 π} = \frac{x}{g}$
  1 mark · Change the subject of a formula
2. ✓
  Square and isolate x $(\frac{t}{2 π})^{2} = \frac{x}{g}$
  $x = g (\frac{t}{2 π})^{2}$ or $x = \frac{g t ^{2}}{4 π ^{2}}$
  1 mark · Change the subject of a formula
8. Question 2.1.3 · March 2017 · Provincial · 4 marks
2.1 Solve for x:
2.1.3 $\frac{x - p}{x - q} = \frac{q}{p}$ (4)
Show the memo (4 ticks)Memo
1. ✓
  Cross multiply $p (x - p) = q (x - q)$
  $p x - p^{2} = q x - q^{2}$
  1 mark · Clear fractions in an equation
2. ✓
  Rearrange terms $p x - q x = p^{2} - q^{2}$
  1 mark · Change the subject of a formula
3. ✓
  Factorise $x (p - q) = (p - q) (p + q)$
  1 mark · Change the subject of a formula
4. ✓
  Solve for x $x = p + q$
  1 mark · Change the subject of a formula

Literal Equations Grade 10 videos

Short lessons from South African teachers first. Videos load only when you tap play, to save your data.

Literal Equations Grade 10 Maths Equations PART 1Miss Martins Maths and Science

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